![]() ![]() We will denote this query as - the same way as the respective argument to Func Suppose a query asks to calculate Func().By “sqrt(x)” we will mean “largest integer less or equal to square root of x”. ![]() Throughout this tutorial “ x⁄ y” will mean “integer part of x divided by y”.We say that index i belongs to segment if L ≤ i ≤ R. We call L left endpoint and R right endpoint of segment. array formed by elements Arr, Arr, …, Arr. Segment is a continuous subarray Arr, i.e. If N and Q are of order 10 5, then this would lead to time limit exceeded.īut what if we answer queries in different order? Can we do better then? Suppose we answer them in order they are asked in the following manner: for i = 0.Q-1: Since the approach is not well-known, in situations where technique is appropriate, you will easily overcome majority of competitors. If the problem was meant to be solved using Mo’s algorithm, then you can be 90% sure that it can not be accepted without knowing it. Due to property #3, the algorithm can solve problems that are unsolvable otherwise. Thus, knowing the method can help you on rare occasions. If we know Func(), then we can compute Func(), Func(), Func() and Func(), each in O(F) time.ĭue to constraints on array immutability and queries being known, Mo’s algorithm is inapplicable most of the time. ![]()
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